b^2+4-4b-16=(b+2)(b-6)

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Solution for b^2+4-4b-16=(b+2)(b-6) equation: 



b^2+4-4b-16=(b+2)(b-6)

We move all terms to the left:

b^2+4-4b-16-((b+2)(b-6))=0

We add all the numbers together, and all the variables

b^2-4b-((b+2)(b-6))-12=0

We multiply parentheses ..

b^2-((+b^2-6b+2b-12))-4b-12=0



We calculate terms in parentheses: -((+b^2-6b+2b-12)), so:

(+b^2-6b+2b-12)

We get rid of parentheses

b^2-6b+2b-12

We add all the numbers together, and all the variables

b^2-4b-12

Back to the equation:

-(b^2-4b-12)



We add all the numbers together, and all the variables

b^2-4b-(b^2-4b-12)-12=0

We get rid of parentheses

b^2-b^2-4b+4b+12-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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